Riddles... errr...
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23:56 Thu 24 Mar 11 (GMT) [Link]
yeah that works. well done . however the sea has changed direction and wiped out the bridge between B and C.
This was meant to be the problem lol. i realised it was wrong when i saw your route lol.
edited as i gave a clue away.
This was meant to be the problem lol. i realised it was wrong when i saw your route lol.
edited as i gave a clue away.
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00:04 Fri 25 Mar 11 (GMT) [Link]
That makes things interesting .... back to the drawing board
00:06 Fri 25 Mar 11 (GMT) [Link]
yes its more challenging now haha. was far too easy before.
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00:10 Fri 25 Mar 11 (GMT) [Link]
Just so I've got this clear before I go and have a think, there are now only 7 bridges and no adverse weather conditions imminent
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00:35 Fri 25 Mar 11 (GMT) [Link]
Well done
buddytobud said:
2good4you_ said:
A basket has 6 eggs in it. A man comes along and takes 2 eggs. A woman comes along and takes 1 egg.
A boy comes along and takes 2 eggs. A girl comes along and takes 1 egg. There is still one egg in the basket. How?
A boy comes along and takes 2 eggs. A girl comes along and takes 1 egg. There is still one egg in the basket. How?
The cheeky little girl took the basket too
Well done
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01:13 Fri 25 Mar 11 (GMT) [Link]
Hmmm, must admit I'm struggling with this one Adam because, from what I remember from graph theory and topology from uni (which as a very very long time ago lol), in order for you to successfully traverse a graph only taking a particular path once then there should be exactly zero or 2 nodes that have an odd number of connecting paths (i.e. source and destination) - this was theorised by someone and proven by someone else, but can't think for the life of me who they were (old age being what it is). So I must have missed something in the description of the puzzle, because the graph I get has all nodes (i.e. the islands) with odd numbers of paths
I think I will have to think about this tomorrow (after the Grand Prix Practice Sessions) because at the moment, I can't see the wood for the trees lol
I think I will have to think about this tomorrow (after the Grand Prix Practice Sessions) because at the moment, I can't see the wood for the trees lol
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01:15 Fri 25 Mar 11 (GMT) [Link]
Woooooooooooooooooohoooooooooooo
buddytobud said:
Hmmm, must admit I'm struggling with this one Adam because, from what I remember from graph theory and topology from uni (which as a very very long time ago lol), in order for you to successfully traverse a graph only taking a particular path once then there should be exactly zero or 2 nodes that have an odd number of connecting paths (i.e. source and destination) - this was theorised by someone and proven by someone else, but can't think for the life of me who they were (old age being what it is). So I must have missed something in the description of the puzzle, because the graph I get has all nodes (i.e. the islands) with odd numbers of paths
I think I will have to think about this tomorrow (after the Grand Prix Practice Sessions) because at the moment, I can't see the wood for the trees lol
I think I will have to think about this tomorrow (after the Grand Prix Practice Sessions) because at the moment, I can't see the wood for the trees lol
Woooooooooooooooooohoooooooooooo
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01:22 Fri 25 Mar 11 (GMT) [Link]
If I am a three digit number and my first digit is seven less than second digit and the second digit is four times that of third digit. What digit am i?
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01:30 Fri 25 Mar 11 (GMT) [Link]
yes
A little boy walked up to his uncle and said, "Uncle, do you know how to make 100 dollars out of ten bills, but not use a single 10 dollar bill?" "What do you mean?" he replied. The little boy replied, " Make 100 dollars out of any ten bills that aren't a 10." And so the uncle tried and gave up. But when the boy tried he got it right. What ten bills, all but the 10 dollar bill, did he use?
A little boy walked up to his uncle and said, "Uncle, do you know how to make 100 dollars out of ten bills, but not use a single 10 dollar bill?" "What do you mean?" he replied. The little boy replied, " Make 100 dollars out of any ten bills that aren't a 10." And so the uncle tried and gave up. But when the boy tried he got it right. What ten bills, all but the 10 dollar bill, did he use?
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02:02 Fri 25 Mar 11 (GMT) [Link]
1x$50 bill, 2x$20bills, 3x$2bills, 4x$1 biils
Name someting that is lighter than a feather but cannot be held by anyone for longer than a few minutes.
Name someting that is lighter than a feather but cannot be held by anyone for longer than a few minutes.
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02:19 Fri 25 Mar 11 (GMT) [Link]
Correct Adam.
Name someone that is 19 but still feels the need to use the word duh?
Name someone that is 19 but still feels the need to use the word duh?
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05:12 Fri 25 Mar 11 (GMT) [Link]
Just bringing this forward so it doesn't get forgotten (got a bit of time between practice sessions )
buddytobud said:
Okies, and yep I know what you mean and this may fall into that category as well lol
Old Boniface he took his cheer,
Then he bored a hole through a solid sphere,
Clear through the center, straight and strong,
And the hole was just six inches long.
Now tell me, when the end was gained,
What volume in the sphere remained?
Sounds like I haven't told enough,
But I have, and the answer isn't tough
Enjoy
Old Boniface he took his cheer,
Then he bored a hole through a solid sphere,
Clear through the center, straight and strong,
And the hole was just six inches long.
Now tell me, when the end was gained,
What volume in the sphere remained?
Sounds like I haven't told enough,
But I have, and the answer isn't tough
Enjoy
12:32 Fri 25 Mar 11 (GMT) [Link]
I dunno tyhe answer to that one, but try this one
A devious army general has taken 4 enemies prisoner, buried them up to their necks in the ground and placed a hat (either red or blue) on each prisoner (there are 2 red hats and 2 blue hats). The prisoners are lined up like so:
X
facing this direction B X R B R
X
the XXX is a wall that they cannot see through
The prisoners cannot see the color of their own hat, and they cannot turn around far enough to see the hat behind them.
The general says that he will will let them go if one of them can correctly state the color of the hat he is wearing (the prisoners will be shot if the given color is incorrect)
There is a catch however, the first word spoken by any of the prisoners must be a color, and that will be their final answer. The prisoners cannot communicate to each other in any way.
Which prisoner knows for sure the color of his hat, and how does he know?
A devious army general has taken 4 enemies prisoner, buried them up to their necks in the ground and placed a hat (either red or blue) on each prisoner (there are 2 red hats and 2 blue hats). The prisoners are lined up like so:
X
facing this direction B X R B R
X
the XXX is a wall that they cannot see through
The prisoners cannot see the color of their own hat, and they cannot turn around far enough to see the hat behind them.
The general says that he will will let them go if one of them can correctly state the color of the hat he is wearing (the prisoners will be shot if the given color is incorrect)
There is a catch however, the first word spoken by any of the prisoners must be a color, and that will be their final answer. The prisoners cannot communicate to each other in any way.
Which prisoner knows for sure the color of his hat, and how does he know?
12:33 Fri 25 Mar 11 (GMT) [Link]
hmmmm, can't get the XXX to line properly, but you get the idea i think
13:49 Fri 25 Mar 11 (GMT) [Link]
B X R B R
The one I underlined shouts out blue.
He knows that the person in front of him is red, so if he was also red, then the person behind him would see 2 red hats in front of him. Because there are 2 red and 2 blue, the person behind him would know that he was blue and would shout. Since the person behind hasn't shouted, then the underlined one knows that he must be different to the person in front of him. The person in front is red, so he knows that he is blue.
The one I underlined shouts out blue.
He knows that the person in front of him is red, so if he was also red, then the person behind him would see 2 red hats in front of him. Because there are 2 red and 2 blue, the person behind him would know that he was blue and would shout. Since the person behind hasn't shouted, then the underlined one knows that he must be different to the person in front of him. The person in front is red, so he knows that he is blue.
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Riddles... errr...
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